4^3n-3=(1/64)^n+1

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Solution for 4^3n-3=(1/64)^n+1 equation: 



4^3n-3=(1/64)^n+1

We move all terms to the left:

4^3n-3-((1/64)^n+1)=0



Domain of the equation: 64)^n+1)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

4^3n-((+1/64)^n+1)-3=0

We multiply all the terms by the denominator


4^3n*64)^n+1)-((-3*64)^n+1)+1=0

We add all the numbers together, and all the variables

4^3n*64)^n+1)-((-192)^n+1)+1=0

Wy multiply elements

256n^4-192)^n+1)+1=0

We do not support enpression: n^4

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